Write a program to check if a given number is a perfect square or not.

Question

Aryan Kumar · Answer

public class PerfectSquareChecker {
   public static boolean isPerfectSquare(int num) {
       int sqrt = (int) Math.sqrt(num);
       return sqrt * sqrt == num;
   }
   public static void main(String[] args) {
       int num = 16;
       if (isPerfectSquare(num)) {
           System.out.println(num + " is a perfect square");
       } else {
           System.out.println(num + " is not a perfect square");
       }
   }
}
In this program, we define a method isPerfectSquare that takes an integer
num as input and returns a boolean value indicating whether or not
num is a perfect square.
To check if num is a perfect square, we calculate the square root of
num using the Math.sqrt method, cast it to an integer, and assign it to the variable
sqrt. If sqrt * sqrt is equal to num, then
num is a perfect square and we return true. Otherwise, we return
false.
In the main method, we test the isPerfectSquare method with the number 16 and print out a message indicating whether or not 16 is a perfect square. You can replace 16 with any other number to test the program with a different input.

Krishnapriya Rajeev · Answer

The following Java program checks whether the given number is a perfect square or not:
and 
public class CheckPerfectSquare {
   public static void main(String[] args) {
      int num = 25;
       if (isPerfectSquare(num))
      {
            System.out.println(num + " is a perfect square.");
       } 
       else 
      {
            System.out.println(num + " is not a perfect square.");
       }
   }
   public static boolean isPerfectSquare(int num) 
   {
       int sqrt = (int) Math.sqrt(num);
       return sqrt * sqrt == num;
   }
}
 Output = Enter a number: 25
            25 is a perfect square.

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Write a program to check if a given number is a perfect square or not.

Revati S Misra

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